DiZ profile - python coding challenges

30

Forgetful Prisoner-vinc 1

I tested this solution, 100% success on 10000 random tests (right hand rule is very useful)! But it does NOT pass your maze test. More

40

suic

One-liner with magic number-suic 1

for golfing, here is your solution in 65 characters ;) check_pangram=lambda t:len(set(filter(str.islower,t.lower())))>25 More

57

veky

Pandemonium-veky 1 1

Nearly same here, sorry for the involuntary copy! More

30

bunnychai

arithmetic-bunnychai 1

Nice solution (quite the same on my own, except I reasoned on k-1). Just a bit surprised by last line ; why not simply ;-) : return max(t, number - s) More

49

Sim0000

56 chars-Sim0000 1

Haha great! Still prefer lambda oneliners though :-P More

8

noobien

First-noobien 1

Strings are also iterable, so you can use _for_ loop and _in_ operator on them directly. More

35

yoichi

First-yoichi 1 1

Smart way to "limit" your grid but here you should use 'infinite' grid by memoizing live cells, truly easier. More

49

Sim0000

67 chars-Sim0000 1 1

I'm surprised, finally we have different solutions but (nearly :-P) same code length! More

35

yoichi

Second-yoichi 1 1

Better than first one, really more readable! But still a niptick: imagine you have 2 live cells (0,0) and (100, 100). Are you really gonna loop through 10,000 (-2) dead cells for nothing? More

44

gyahun_dash

set-gyahun_dash 1

That's a nice solution! Just one niptick, no need to cast output to `list` ;-) More

10

1089

First-1089

Not portable. You might consider recursive function More

24

madmanbob

First-madmanbob

Simple, but you don't need "return False" statements ;) More

5

arunnadda

Count Inversions-arunnadda

You should look at _for_ loop. Or if you really want to stick with _while_ loop: if list[i] > list[j]: output += 1 j += 1 else: j += 1 Here it is better to write, simpler and more readable: if list[i] > list[j]: output += 1 j += 1 Or even bette More

34

DiZ

I don't love Python!-DiZ

What if you execute this code with Python 2? :-O More

23

fantakeshi

Multiple assignment in one line.-fantakeshi 1

Maybe simply using Python chained assignments __eq__ = __ne__ = __gt__ = __lt__ = __ge__ = __le__ = lambda a, b: True More

2

Codenburger

First, so much fun :D-Codenburger

Note that you can make several operations on the same line and you can also factorize common code (both in _if_ and _else_ statements for better readibility. More