15
Last seen 9 years ago
Member for 9 years, 11 months, 9 days
Difficulty Normal
Very nice code! If you wanted to be more concise, you could just use 'args' everywhere you used arg_list.
def checkio(*args):
if len(args) == 0:
return 0
return max(args) - min(args)
Works just as well.
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There is no need to sort after every number is appended to the 'number' list, once after all numbers are appended would work.
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Minimized iterations, however not sure if data manipulations were optimal-ilpalazzo_sama
Well named variables and well commented :-)
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Nice code! If you wanted to be more concise, you could make three changes.
1, args is treated as a tuple (a list you can't edit) so turning them into a list is unnecessary.
2. The '*' is not needed anywhere except in the function argument.
3. Checking to see if there is only 1 argument isn
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First-stephan233
Am I reviewing my own code? :-) I guess there was one obvious way to do it, what with the hints and all.
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Sets can not preserve order, so sorting the list before making it a set in lines #2 and #3 is immediately undone. Also, the "sorted()" function returns a list, so "sorted(list(...))" could just be "sorted(...)".
def checkio(first, second):
f = set(first.split(','))
s = set(s
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abs() is already a function, the lambda is not needed.
def checkio(numbers_array):
return sorted(numbers_array, key=abs)
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Very nice code :-)
If you didn't want to type out math.XXX each time, you could alter your import statement like this:
from math import pi, sqrt, atanh, asin
print(pi)
>>> 3.1415....
print(sqrt(4))
>>> 2.0
If you want to get even fancier...
from math impor
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Very cool recursive function! It would probably start to run slowly as n increases though because triangle(n) is called once on each number for every n above it. triangle(4) calls triangle(1) 4 times, for instance.
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Very clear code, I like it. Why do you convert 'attacked' back into a list after every minute? You could leave it as a set if you wanted.
def capture(matrix):
time = 0
attacked = {0}
new_infected = []
while any(matrix[a][a] > 0 for a in range(len(matr
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Very nice! If you wanted to shorten the code however,
if cmd[1] == "O":
try: somme += int(stack.pop())
except: pass
Can be:
if cmd[1] == 'O' and stack:
somme += int(stack.pop())
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Nice, clear code. Just a note though, it's considered bas practice to use a built in function as a variable name (min for minutes is already used for the minimum function).
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