Riddick profile - python coding challenges

11

soloshowing

First-soloshowing

You may write if-else in a one line, for example: return text if text[-1] == '.' else text + '.' More

10

yuta0613

My first answer-yuta0613

Looks good, maybe will be better change 5 strings of code in one, for example: return array[n]**n if len(array) >= (n+1) else -1 And a little refactoring you can check len(array) without more or equal but only more, e.g.: return array[n]**n if len(array) > n else -1 More

6

margot

First-margot

You may write in one line: return True if all(elem == list[0] for elem in list) else False More

11

ki1ler

First-ki1ler

You may change a some part of code for more readable. For example, you may check to %15 firstly and return str(number) in the else block code: if number % 15 == 0: return 'Fizz Buzz' ... else: return str(number) More

22

Sioul

All-Sioul

Interesting approach, I recommend to look on builtin library `string` with property `ascii_lowercase` More

4

Arahabakan

First-Arahabakan

What do you think about recursion? More

33

kkkkk

Use an end range that is half the desired sum-kkkkk 1

Interesting solution, But I think with `while` will be more clear More

13

novelworm

First-novelworm 1

You may not use 0 in data[0:limit] It will be like data[:limit] More

12

ElisaZeneli

First-ElisaZeneli 1

Please use lambda function instead nested function. Thanks! Nice solution! More

15

wii_caiji

one_line-wii_caiji

Maybe the shortest solution that I saw. More

9

spiros738

First-spiros738

You can merge in one line of code. More

12

armandolios

Sort 'name', then 'price'-armandolios

Why do you use `list.sort(data, key = lambda k: k["name"])` ? You can use only this one `list.sort(data, key = lambda k: k["price"], reverse = True)`. list.sort - not obviously will be nice avoid this construction. More