Nov. 23, 2017, 1:40 p.m. |
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nickie: Well done. Using [itertools.permutations](http://docs.python.org/3/library/itertools.html#itertools....
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Nov. 23, 2017, 1:39 p.m. |
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veky: abs is a function, no need to lambdize it. :-)
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Feb. 28, 2014, 11:29 p.m. |
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bryukh: Yeah, we have problems with eternal loops (you don't see a problem test). We are going to fix it wit...
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Feb. 20, 2014, 4:39 p.m. |
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nickie: A little shorter, using the array as a condition instead of len(a) > 0. checkio = lambda a: sum(a[::...
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Feb. 3, 2014, 9:58 p.m. |
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Marigold: Nice solution, but not very efficient. Imagine you have something similar to Fibonnaci sequence when...
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Jan. 23, 2014, 10:47 p.m. |
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Amachua: Compare to mine your solution he's realy easy to read but it isn't O(1) ;)
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Jan. 20, 2014, 10:44 p.m. |
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ysenko: romanmappings = {1: "I", 4: "IV", 5: "V", 9: "IX", 10: "X", You can get rid of ... sorted(romanmappi...
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Jan. 20, 2014, 10:44 p.m. |
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username724: Pretty good. Could be simplified a bit, like make the dictionary backwards to start with. And instea...
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Jan. 19, 2014, 5:43 p.m. |
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Dragonfly555: Didn't like the use of letters as variables. it's unreadable. a plus for you is that you didn't use ...
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