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Hrvoje
http://blog.hrvoje.org/
Last seen 2 years ago
Member for 10 years, 1 month, 12 days
Difficulty Normal
Trying to make everything a one-liner and sometimes failing miserably. :)
I learned about the algorithm here... check it out, it's easier to understand than the strict and formal math textbooks: https://www.youtube.com/watch?v=QYrpHE8iDGg
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Might be easier to write if a+b+c <= 2*max...? You also don't really need the else.
Niiiice work! :)
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It might be more "*pythonic*" to import string and then use string.ascii_lowercase, but I like this solution - simple and interesting. Well done! :)
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This is a clever way, well done!
**all** is also very handy and could come useful, for example:
return all(chr(i) in text.lower() for i in range(97, 123))
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Cool! You could also simply return the first==second. If both sides compare equal, it will return true. :-)
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Short-StefanPochmann
This is very elegant, especially the odd ^=1 followed by a multiplication. Megalike! :)
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Very cool use of string.join('()'). It does remind of a female body part, though. Naughty Veky. :)))
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This is *freakishly* awesome and clever, I struggled with operators and generators, you just used sets ... boy, do I have a lot to learn. :-P
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First-divided.hr
You don't need the stuff after the 1, simply count('1') will work just fine. :)
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First - Number Base-divided.hr
That's nice and clean. Good practice is not catching all exceptions, just the one you want to handle, otherwise programs fail silently while appearing to work.
In this case, try **except ValueError:**
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First - X/O Referee-divided.hr
You got it working, now try writing it again without the boring repetitions. :)
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Very nice, clear and effective! :) Here are few tips:
You don't need the max(max(pyramid)), the maximum is in the last sublist, so a simple **max(pyramid[-1])** is enough.
Instead of list comprehension in the 2nd line, you could have used **map(list, pyramid)**.
*for i in range(len(something))*
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Simple-StefanPochmann
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I love the max(cells, key=your function... approach. My respect, one of the best coders I've seen on the site.
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