40
oduvan
15 34 57
10059/ 10664
Last seen 1 day ago
Member for 13 years, 10 months, 22 days
Difficulty Easy
love it!

Best reviews / Newest reviews
First-likewind
line 7-9: you can do substring check using operator `in` >>> 'are' in 'aresjfhdskfhskd' True More
My first solution for min/max task.-Oleksandr_Zaliskyi
this is weird. Max and min functions are so different. More
All the Same-c135260 1
line 5 can be simpler, without using True and False. How? More
So simple...-Phil15 1
I wouldn't say this is a very fast way to solve. You should go through all the elements of instructions 4 times. More
Using set()-Eric_Meyer
you can also say if elements > 1 More
The shortest-MrPod 1
wana go with Creative category? More
First-likewind
line 10-12: can be replaced by: return n == len(elements) More
First-sv.pero
line 3: You might want to use text.replace instead of word.strip More
First-sv.pero
it is better to use replace here More
First-sv.pero
line 9, 11, 13: can be `return` here More
First-sv.pero
line 6: just `set(data)` line 8: just `in s` More
First-sv.pero
line 3: a = lambda x: func(x) is the same as just a = func More
First-Padre 1
вопрос, дойдет ли программа когда-нибудь до 14ой строки? More
First-Vlad2018 1
I don't think that solution with RE can be speedy More
Conversion from CamelCase-anuarora
I wouldn't call list variable somehow_string More
2 functions-likewind 1
line 1-21 - this is exactly how dicts work More
First-alex.kov 1
я бы `text.find(begin)` и `text.find(end)` сохранил в отдельную переменную, а ты то пересчитываешь это слишком часто. а еще, для проверки наличия символа в строке можно просто использовать оператор **in** вместо метода **find** More
First-alex.kov 1
haha :) рад, что ты запомнил :) More
First-Padre
вспоминаем лекцию по приведению к булеану. как сократить `if (number % 3) == 0:` ? More
First-Valentyna_Zelik
в 12ой строке вместо answer= может быть return? More
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