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artem rudenko
Last seen 10 months ago
Member for 13 years, 3 months, 3 days
Difficulty Normal
Software Testing Engineer
Intersting but think that is not the clearest solution for this task
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Very pythonic rotate. The only thing to add is that there is no need to use list and tuple calls in your code - it will work without them.
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Awesome, i spent a lot of time trying to find a formula you have used.
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The only thing to add from me is that is not required to call list on map, e.g you can replace:
m=list(map(list,_m))
with
m=map(list,_m)
Also the 'rest' part:
#mark rest
for y in range(len(m)):
for x in range(len(m[y])):
if m[y][x]=='.': m[y][x]='S'
retur
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Nice, the small addition is that:
list(range(n)) + list(range(n))
can be replaced with:
range(n) + range(n)
or:
range(n)*2
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Simulated-PositronicLlama
Really cool: nice comments, very short code, very clear
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Nice. The only notice here is that you can use collections.deque and rotate method specifically.
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It's not a good practice to use 'next' as a variable name. You can replace two 'for i in range(-1, 2)' with 'itertools.product(range(-1,2), range(-1,2))'
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+2 for the fastest deque, one thing is that you can move list from 'for displacement in [(1,0), (0,1), (-1,0), (0,-1)]:' to outside or to replace it with 'for displacement in ((1,0), (0,1), (-1,0), (0,-1)):'
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Think it can be simplified to:
def checkio(data):
return 0 if not len(data)else data[0]+checkio(data[1:])
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Very good, note that line 4:
any((True for x, y in groupby(l) if len(list(y)) >= 4))
Can be updated to:
any(True for x, y in groupby(l) if len(list(y)) >= 4)
Also you can save matrix size e.g. 'len(matrix)' into a variable and use it.
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