Wow! I used .isupper() and .isnumeric() and .isspace() without realising this could be done More

There was no need for using i. You could simply get the answer by using text.islower() instead of using text[i].islower() More

This is a good solution. Very clear. But you don't need to specify the separator as a parameter if it's space and you don't need to specify the "== True" part to check if d.isnumeric() is True More

This is really good. I didn't think of this. More