30
Bunny Chai
Last seen 2 years ago
Member for 11 years, 5 months, 24 days
Difficulty Normal
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how about
assert shot((0, 0), (1, 1), (3, 3), (2, 2)) == 0, "shot in butt of wall"
?
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we use similar strategy, but mine is slightly more complicated,
i think this is quite stable, so far, yours and mine are the only non-random solutions that could pass 10000 random mazes...
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for integer inputs, no floating point comparison and arithmetic...
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because the matrix is special, so as the inverse, so no need to find inverse or do elimination explicitly...
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overkill but nice formulation of transition matrix
at each step, either +1 or -1, so becomes 1-i/len or i/len, to not to be picked or to be picked
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we got the same formula
but I don't bother to write down the proof...
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Alternatively, solved using concepts of projective geometry in [here](http://www.checkio.org/mission/cakes-rows/publications/bunnychai/python-3/projective-geometry/).
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Rough solution-pcresolver
u may use:
summary = [0] * 365
or just use Counter, in which the cnt is automatically set to 0 for u
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def checkio(data):
list(map(add, data))
return total
just a little bit more simplified...
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