20
Last seen 1 month ago
Member for 2 years, 12 months
Difficulty Normal
Interesting for me. Through your solution (in order to understand it), you put me in the way to study the regular expression operations. Thanks!
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First-aplayer999
Very interesting way to check the alphanumeric constraints:
__**if {True,False}.issubset([x in '0123456789' for x in password]):**__
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long one line :)-tkachuk.constantine
I have learn a couple of things on this solution. Thanks!
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With nested IF, ALL and ANY-anazarovsky
Clean and clear. Thanks for showing me the function "all".
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acc_pw_v-re-nazarstakhovskyi
1
Masterclass for me about re.search usage:
_**re.search("[Pp][Aa][Ss]{2}[Ww][Oo][Rr][Dd]", password)**_
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Nice and compact way to code the solution. I woul like I could "think" my codes like this!
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Sorry, I do not understand very well why create a dict to convert again to a list.
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Nice alternative way to evaluate the ascending condition.
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Very interesting for me to split in two the lista ("special" cases and "normal" cases).
Also I have learn somethig new for me about the use of lambda. Thanks.
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First-Jose_Facundo_Bogado_Navarrete
1
I definitely have to learn and train more about the use of "lambda".
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57 symbols-tkachuk.constantine
Short and smart! I think it might be in "speedy" category.
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