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Last seen 4 years ago
Member for 10 years, 6 months, 27 days
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Learned Python through pyquick, blogs, and checkio. Trying to get good enough to help others with Python. 2LwithGA
Good. Using the "ord" function we can define a function "alphanumber" to replace the parallel array look-up. With this the code becomes. If "ord" didn't exists we could use string indexing as commented out.
def checkio(str_number, radix):
alphanumber = lambda x:ord(x)-55 # e
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Good. The method "join" is helpful here. Similar to "join" in javascript.
# '77'.join(['aaa','bbb','ccc']) --> 'aaa77bbb77ccc'
def left_join(phrases):
return ','.join(phrases).replace('right','left')
Join is useful for writing formatted data to files. Also we can use it to join
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First-rafaelbsb
Nice. Good use of itertools.groupby. For checking isalpha, you can use str.isalpha directly rather than creating a lambda. Both are the function taking a character x as input and returning whether x is alpha as output. Also, endswith may be a little nicer than subj[-3:].
def is_stressful(su
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Nice. Nicer with getting rid of "c for c in." Even nicer with lambda. No need for r=0, right?
checkio=lambda a:a[-1]*sum(a[::2]) if a else 0
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Good, but move your lambda. No need for it after key: "key=lambda n:abs(n)" is the same as "key=abs".
checkio = lambda i:sorted(i,key=abs)
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Like the use of Floyd's algorithm, and itertools.product is useful for many of these problems (I keep forgetting it).
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One line with double negation-Viktor_Shulgin
Not bad. Not not good. But converting the result to a bool may be clearer.
def checkio(data: str) -> bool:
return bool(len(data) >= 10 and re.search("[a-z]+", data) \
and re.search("[A-Z]+", data) \
an
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Good. You can shorten "len(args) > 1" to "args[1:]" if you like. You can also perform the if-else in a single line "args = list(args) if len(args)>1 else args[0]"
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Good. You can shorten array[len(array)-1] to just array[-1]. You can also shorten "if len(array) != 0" to "if len(array)" or just "if array".
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Good. When finding the min and max value in the dictionary, we can set the key to the "get" method rather than creating a lambda.
def fastest_horse(horses):
leaderboard = {}
for race in horses:
places = {position: int(time.split(':')[0]) * 60 + int(time.split(':
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For checking a dictionary, you can use "get" to supply a default value to return in case the key is not in the dictionary. With this you have:
def checkio(text):
text = text.lower()
freq = {}
for letter in text:
if letter.isalpha():
#if lette
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First-Jarik_Krimets
Good. You can use "get" to provide a default return value in case a key is not in the dictionary. Also, you could use collections.defaultdict.
def checkio(text):
dict_letters = dict()
for a in text:
if a.isalpha():
#if a.lower() in dict_letters:
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