I think this is not the best solution. return 551 if number==1000 this decision is better FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"] SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", More

good solution using ord() and join() More

clean code. but this task can be solved in a single line using the join() More

clean code. One-line solution using join().good work! More