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ogoro
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Awesome Team Mykhailo Ohorodnikov https://ogoro.me
Last seen 1 year ago
Member for 3 years, 8 months, 11 days
Difficulty Normal
Python developer with telecom background - Kyiv, Ukraine

Best reviews / Newest reviews
classic-kdim 2 1
thanks a lot for ... Ellipsis! https://stackoverflow.com/questions/772124/what-does-the-ellipsis-object-do https://www.python.org/dev/peps/pep-0484/#callable very interesting) More
Modular Cramer's rule-martin_b 2
Thanks a lot for great solution! i have optimized EGCD a little bit - according to Wikipedia) could you please explain "idm"?)) https://py.checkio.org/mission/hubspot-amulet/publications/ogoro/python-3/cramer-egcd/ More
v2: unoriented lines, generate square lines-Phil15 1 1
thanks for the interesting solution! i also used pairwise from recipes and superset check) did you know that edges.issuperset(_square_lines(size, start)) is equaivalent to _square_lines(size, start) <= edges ?) More
try except-kdim 1
thank you for very clear translation dictionary!) More
Rotate/turn. Dimensions? Spaces? Sum 7?-Phil15 1
what would you say about [perimeters](https://py.checkio.org/mission/paper-dice/publications/ogoro/python-3/perimeters/) and 1-liner?) More
First-flpo 1
interesting recursive generator, thank you!) More
First-eugen2005 1 1
you could also use: return sorted(numbers_array, key=abs) :) More
Replace strptime strftime-Striga 1
you could use: dt = T.strptime(time, "%I:%M %p") :) More
x or zeros.add(i)-flpo 1
thank you for 'or' statement in comprehension! or zeros.add(i) More
Flatten a List-ddavidse 1 1
interesting parser) you also could use: n = [x for x in s if x not in '[] '] # eliminate brackets and spaces and: if not n: return [] More
re.match()-kurosawa4434 1
thank you for very clear regex example! More
dict-Sim0000 1
what would you say about [perimeters](https://py.checkio.org/mission/paper-dice/publications/ogoro/python-3/perimeters/) and 1-liner?) More
One line Regex-lucas.stonedrake 1 1
you could use: return len(password) > 6 and re.search('[0-9]', password) and not password.isdigit() or: return len(password) > 6 and any(letter.isdigit() for letter in password) and not password.isdigit() instead of: return True if len(password) > 6 and re.search('[0-9]', password) More
using collections.deque-tvylormvde 1
you could also use: lst.rotate(1) https://docs.python.org/3/library/collections.html#collections.deque.rotate More
First-MartinAch 1 1
i suppose it could also work without conversion to list: return sorted(numbers_array, key=abs) :) More
from datetime import datetime-V.Shkaberda 1 1
it turned out - it works even without .upper() More
First-colinmcnicholl 1 1
thank you for extremely clear and documented code! More
import combinations, starmap & gt-flpo 1
interesting usage of starmapping an operator on combination tuples, thank you) More
Compress List-ddavidse 1
nice solution) you could also use: num = None to allow -1 to be present in items More
zip(it, it)-Sim0000 1
interesting pair selection with zip(it, it) - thank you) More
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