15
Last seen 2 years ago
Member for 9 years, 11 months, 15 days
Difficulty Normal
I usually dont write comments, but this one is really good solution!
Very clear and easy to understand!
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very beautiful approach in solving this problem. At the beginning I was trying to make my solution something similar to yours but I failed. So I used stack. Now yours solutions opened my eyes. Thank you
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QQ-Ruo-Shan_Liu
the for loop is not necessary. You can just check if '.' is the last char text_1[-1] == '.' and append the already capitalized char with text+= text_1[1:]
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why not return sorted(goods, key = lambda x: x['price'], reverse = True)[:number] ?
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Very clear and easy to understand solution. This deserves more votes
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