Hi monkshorin, Thank your for publication and great code provided. Can you be so kind to tell how this trick called "[0::2]". I'm new in python and used old-school code (with for loop and counter variable to find even elements). Thank you in advance. Regards, Olexander.Ukraine More

Thank you for publication. endswith - is proper solution in this case. But as for me "if statement" may be much shorter, like this: if w1 != w2 and w1[::-1].find(w2[::-1]) == 0 {You reversed words and suffix and compared it) Educational: [start:end:stride], and string function find() More

Attention!!! Divmod() in action ;) Really Anti - Bicycle function. Well done!!! More